If an oil drop of weight `3.2xx10^(-13) N` is balanced in an electric field of `5xx10^(5) Vm^(-1)`, find the charge on the oil drop.

If an oil drop of weight 3.2xx10^(-13) N is balanced in an electric field of intensity 5xx10^(5) V/m, find the charge on oil drop.

In 1909, Robert Millikan war the firest to find the charge of an electron in his now-famous oil-drop experiment. In that experiment, tiny oil drops were sprayed into a uniform electric field between a horizontal pair of opposite charged plates. The drops were pbserved with a magnitue eyepiece, and the electric field was adjusted so that upward force on some negatively charged oil drops was just sufficient to balance the downward force of gravity. That is, when suspended, upward force qE just equaled mg. Millikan accurately measured the charges on many oil drops and found the values to be whole number multiples of 1.6xx10^(-19)C- the charge of the electron. For this, he won the Nobel prize. If a drop of mass 1.08xx10^(-14)kg remains stationary in an electric field of 1.68xx10^(5)NC^(-1) , then teh charge of this drop is

In 1909, Robert Millikan war the firest to find the charge of an electron in his now-famous oil-drop experiment. In that experiment, tiny oil drops were sprayed into a uniform electric field between a horizontal pair of opposite charged plates. The drops were pbserved with a magnitue eyepiece, and the electric field was adjusted so that upward force on some negatively charged oil drops was just sufficient to balance the downward force of gravity. That is, when suspended, upward force qE just equaled mg. Millikan accurately measured the charges on many oil drops and found the values to be whole number multiples of 1.6xx10^(-19)C- the charge of the electron. For this, he won the Nobel prize. If a drop of mass 1.08xx10^(-14)kg remains stationary in an electric field of 1.68xx10^(5)NC^(-1) , then teh charge of this drop is

In Millikan's oil drop experiment, an oil drop mass 60 xx 10^(-6) kg is balanced by an electric field of 10^(6) V//m . The charge in coulomb on the drop, assuming g = 10 m//s^(2) is

A charged oil drop weighing 1.6 xx 10^(-15) N is found to remain suspended in a uniform electric field of intensity 2 xx 10^3NC^(-1) . Find the charge on the drop.

An oil drop with 10 excess electrons is held stationary under a constant electric field of 3 xx 10^(4) NC^(-1) in Millikan oil drop experiment. The density of the oil is 1.26 xx 10^(3) kg m^(-3) . Calculate the radius of the drop.