3x-4y=10,4x+3y=5

Find the value of (x-y) , if 3x+4y=11,4x+3y=10

The lines parallel to the normal to the curve x y=1 is/are 3x+4y+5=0 (b) 3x-4y+5=0 4x+3y+5=0 (d) 3y-4x+5=0

Solve the equations graphically 3x+4y=10 and 4x-3y=5 .

The sides of a triangle are 3x+4y, 4x +3y and 5x +5y where, x, y gt 0, then the triangle is-

Prove that the three lines 5x+3y-7=0, 3x-4y=10, and x+2y=0 meet in a point.

3x-4y=-7,5x-2y=0

2x+3y=0 3x+4y=5

3x+4y=-5,x-y=-4