`(999)^2-(998)^2=?` 1992 (b) 1995 (c) 1997 (d) 1998

f:R rarr R is given by f(x)=(a^(x))/(a^(x)+sqrt(a)) , x in R , then f((1)/(1997))+f((2)/(1997))+.....+f((1995)/(1997))+f((1996)/(1997))= (A) 997 (B) 998 (C) 1997 (D) 1998

999.99+99.99+9.99=? (a) 1019.89 (b) 1099.88(c)1108.99 (d) 1109.99 (e) None of these

(2005)^(2)-(1995)^(2)= ?

The value of 999(995)/(999)xx999 is (a) 990809(b) 998996(c)998999 (d) 999824

The simplified value of 1998^(2)-1997^(2)+1996^(2)-1995^(2)+1994^(2)-1993^(2) is (a) 11953(b)11958(c)11963(d)11973

2^(1998)-2^(1997)-2^(1996)+2^(1995)=" K."2^(1995)"

The following data gives the amount of manure (in thousand tonnes) manufactured by a company during some years: Year, 1992, 1993, 1994, 1995, 1996, 1997 Manure (In thousand tonnes), 15, 35, 45, 30, 40, 20 Represent the above data with the help of a bar graph. Indicate with the help of the bar graph the year in which the amount of manure manufactured by the company was maximum. Choose the correct alternative: The consecutive years during which there was maximum decrease in manure production are: 1994 to 1995 (b) 1992 and 1993 1996-1997 (d) 1995 and 1996

The value of 998(2)/(17)+998(3)/(17)+998(5)/(17)+998(8)/(17)+998(16)/(17) is (a) 4990( b) 4992(c)9998(d)10000