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(9^6+1) when divided by 8, would leave a...

`(9^6+1)` when divided by 8, would leave a remainder of 0 (b) 1 (c) 2 (d) 3

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RS AGGARWAL-NUMBER SYSTEM-All Questions
  1. (3^(25)+3^(26)+3^(27)+3^(28)) is divisible by 11 (b) 16 (c) 25 (d)...

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  2. (4^(61)+4^(62)+4^(63)+4^(64)) is divisible by (a) 3 (b) 11 (c) 1...

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  3. (9^6+1) when divided by 8, would leave a remainder of 0 (b) 1 (c) ...

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  4. If n even, (6^n-1) is divisible by 6 (b) 30 (c) 35 (d) 37

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  5. If (12^n+1)\ is divisible by 13, then n is (a) 1 only (b) 12 only (c...

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  6. 25^(25) is divided by 26, the remainder is 1 (b) 2 (c) 24 (d) 25

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  7. If (67^(67)+67) is divided by 68, the remainder is 1 (b) 63 (c) 66...

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  8. One less than (49)^(15) is exactly divisible by 8 (b) 14 (c) 50 (d...

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  9. The remainder when 7^(84) is divisible by 342 is 0 (b) 1 (c) 49 (d)...

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  10. The remainder when 2^(60) is divided by 5 equals 0 (b) 1 (c) 2 (d)...

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  11. By how many of the following numbers is 2^(12)-1 divisible ? 2, 3,5, 7...

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  12. The remainder when (15^(23)+23^(23)) is divided by 19, is 0 (b) 4 ...

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  13. When 2^(256) is divided by 17, the remainder would be 1 (b) 14 (c)...

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  14. 7^(6n)-6^(6n), where n is an integer > 0, is divisible by 13 (b) 1...

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  15. It is given that (2^(32)+1) is exactly divisible by a certain number. ...

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  16. The number (2^(48)-1) is exactly divisible by two numbers between 60 ...

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  17. n being any odd number greater than 1, n^(65)-n\ is always divisible ...

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  18. Let N=55^3+17^3-72^3dot Then, N is divisible by both 7 and 13 (b) bot...

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  19. Find the last two digits of N . 00 (b) 13 (c) 19 (d) 23

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  20. Find the remainder when N is divided by 168. 33 (b) 67 (c) 129 (d) ...

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