`6/(5-5/3)+(4-2/(4-1/2))/(5-3/2)-2/5` of `{6/9+2/3\ of1/2}=?` (a) `1 1/3` (b) `2(13)/(49)` (c) `1 7/(16)` (d) `2 3/5`

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

(7(1)/(2)-5(3)/(4))/(3(1)/(2)+?)-:((1)/(2)+1(1)/(4))/(1(1)/(5)+3(1)/(2))=0.6 a) 4(1)/(3)(b)4(1)/(2) (c) 4(2)/(3) (d) None of these

If A=[(2)/(3)1(5)/(3)(1)/(3)(2)/(3)(4)/(3)(7)/(3)2(2)/(3)] and B=[(2)/(3)(2)/(5)1(1)/(5)(2)/(5)(4)/(5)(4)/(5)(7)/(3)(6)/(5)(2)/(5)], then compute 3A_(-)=5B

(3)/(4)(1+(1)/(3))(1+(2)/(3))(1-(2)/(5))(1+(6)/(7))(1-(12)/(13))=?(1)/(5)( b )(1)/(6)(c)(1)/(7) (d) None of these

1(5)/(6)+[2(2)/(3)-{3(3)/(4)(3(4)/(5)-:9(1)/(2))}]

5(5)/(6) + [2(2)/(3) - [3(3)/(4) (3(4)/(5) div 9(1)/(2))]]

When ((1)/(2)-(1)/(4)+(1)/(5)-(1)/(6)) is divided by ((2)/(5)-(5)/(9)+(3)/(5)-(7)/(18)), the result is 2(1)/(18) (b) 3(1)/(6)(c)3(3)/(10) (d) 5(1)/(10)

(5)/(6) -: (6)/(7) xx ? - (8)/(9) -: 1 (2)/(5) -: (3)/(4) xx 3 (1)/(3) = 2(7)/(9)