If `2p+3q=18` and `2p-q=2` , then `2p+q=?` (a) 6 (b) 7 (c) 10 (d) 20

If p and q are the roots of the equation x^2-p x+q=0 , then p=1,\ q=-2 (b) b=0,\ q=1 (c) p=-2,\ q=0 (d) p=-2,\ q=1

P ** q = p^2 - q^2 p $ q = p^2 - q^2 p $ q = p^2 + q^2 p @ q = pq + p + q p Delta q = Remainder of p/q p © q = greatest integer less than or equal to p/q . If p = 8 and q = 10 , then the value of [(p $ q) Delta (p @ q)] ** [(q ** p) @ (q © p)] is :

P ** q = p^2 - q^2 p % q = p^2 - q^2 p $ q = p^2 + q^2 p @ q = pq + p + q p Delta q = Remainder of p/q p © q = greatest integer less than or equal to p/q . If p = 11 and q = 7 , then the value of (p ** q) @ (p $ q) is:

2p+3q=18 and 4p^2+4pq–3q2−36=0 then what is (2p+q) equal to?

If p=3 and q=2 , then (3p-4q)^(q-p)div(4p-3q)^(2q-p) =_______

If sec alpha and alpha are the roots of x^2-p x+q=0, then (a) p^2=q(q-2) (b) p^2=q(q+2) (c)p^2q^2=2q (d) none of these

p @ q = p^2 - 20 if p > q , q 2 q = p^2 + 20 if p le q, then for a = 5 and b = 4 the value of [(a @ b) @ (a @ b)] - [(b @ a) @ (b @ a)] is :

2p+3q=18 and 4p^(2)+4pq-3q^(2)-36=0 then what is (2p+q) equal to?