For `a> b>c>0`, if the distance between `(1,1)` and the point of intersection of the line `ax+by-c=0` is less than `2sqrt2` then,

For a>b>c>0, if the distance between (1,1) and the point of intersection of the line ax+by-c=0 and bx+ay+c=0 is less than 2sqrt(2) then,(A)a+b-c>0(B)a-b+c 0(D)a+b-c<0

For a gt b gt c gt 0 if the distance between (1,1) and the point of intersection of the lines ax + by +c=0 and bx + ay+c=0 is less than 2sqrt2 then

The distance between the point of intersection of the two lines 2009x^(2)+2010xy+2011y^(2)=0 and the point (1,1) is

The square of the distance between the origin and the point of intersection of the lines given by ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 , is

What is the distance between the points A(c,0) and B(0,-c)?

Show that the equation of the straight line through (alpha,beta) and through the point of intersection of the lines a_(1)x+b_(1)y+c_(1)=0 and a_(2)x+b_(2)y+c_(2)=0 is (a_(1)x+b_(1)y+c_(1))/(a_(1)alpha+b_(1)beta+c_(1))=(a_(2)x+b_(2)y+c_(2))/(a_(2)alpha+b_(2)beta+c_(2))

If 2 is a root of ax^(2)+bx+c=0 then point of concurrence of lines ax+2by+3c=0 is