If `(x+1)/(x-1)=a/b` and `(1-y)/(1+y)=b/a` , then the value of `(x-y)/(1+x y)` is `(2a b)/(a^2-b^2)` (b) `(a^2-b^2)/(2a b)` (c) `(a^2+b^2)/(2a b)` (d) `(a^2-b^2\ )/(a b)`

If (a+b)x =a and (a+b) y = b then the value of (x^(2)+y^(2))/(x^(2)-y^(2)) is

If a,b>0, then minimum value of y=(b^(2))/(a-x)+(a^(2))/(x)in(0,a) is (a+b)/(a) (b) (ab)/(a+b)(1)/(a)+(1)/(b) (d) ((a+b)^(2))/(a)

If (x)/(a)-(y)/(b) tan theta =1 and (x)/(a) tan theta +(y)/(b)=1 , then the value of (x^(2))/(a^(2))+(y^(2))/(b^(2)) is

If (x)/((b-c)(b+c-2a))=(y)/((c-a)(c+a-2b))=(z)/((a-b)(a+b-2c)) then the value of (x+y+z) is :

(a-b)x+(a+b)y=a^(2)-2ab-b^(2)(a+b)(x+y)=a^(2)+b^(2) find x and y

If 2x=a+a^(-1) and 2y=b+b^(-1) then find the value of xy+(sqrt((x^(2)-1)(y^(2)-1)))

If x=a sec theta and y=b tan theta, then b^(2)x^(2)-a^(2)y^(2)=( a )ab(b)a^(2)-b^(2)(c)a^(2)+b^(2) (d) a^(2)b^(2)

If x=(a+b)/(a-b),y=(b+c)/(b-c),z=(c+a)/(c-a) then the value of ((2x+2)(4y+4)(z+1))/((x-1)(y-1)(z-1)) is equal to

If the origin is shifted to the point ((a b)/(a-b),0) without rotation, then the equation (a-b)(x^2+y^2)-2a b x=0 becomes (A)(a-b)(x^2+y^2)-(a+b)x y+a b x=a^2 (B)(a+b)(x^2+y^2)=2a b (C)(x^2+y^2)=(a^2+b^2) (D)(a-b)^2(x^2+y^2)=a^2b^2