A number consists of two digits such that the digit in the tens place is less by 2 than the digit in the units place. Three times the number added to `6/7` times the number obtained by reversing the digits equal 108. The sum of the digits in the number is a. 6 b. 7 c. 8 d. 9

A number consists of two digits. The digit in the ten's place exceeds the digit in the unit's place by 4. The sum of the digits is 1/7 of the number. The number is :

The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is

In a two-digit number the digit in the unit's place is three times the digit in the tenth's place. The sum of the digits is equal to 8. Then, what is the number?

The ratio of a 2-digit number to the sum of its digits is 7: 1. If the digit in the ten's place is 1 more than the digit in the one's place, then the number is

A two digit number ab is added to another number ba, which is obtained by reversing the digits then we get a three digit number. Thus a + b equals to :

In a two –digit positive number, the digit in the unit’s place is equal to the square of the digit in ten’s place, and the difference between the number and the number obtained by interchanging the digits is 54. What is 40% of the original number? a. 15.6 b. 24 c. 37.2 d. 39 e. none of these