A straight line through the origin 'O' meets the parallel lines `4x +2y= 9` and `2x +y=-6` at points P and Q respectively. Then the point 'O' divides the segment PQ in the ratio

A straight line through the origin 'O' meets the parallel lines 4x+2y=9 and 2x+y=-6 at points P and Q respectively.Then the point 'divides the segment PQ in the ratio

A straight line through the origin O meets the parallel lines 4x+2y=9 and 2x+y+6=0 at points P and Q respectively. Then the point O divides the segement P Q in the ratio (1) 1:2 (2) 3:4 (3) 2:1 (4) 4:3

A straight line through the origin o meets the parallel lines 4x+2y= 9 and 2x +y+ 6=0 points P and Q respectively. Then the point o divides the segment PQ in the ratio: : (A) 1:2 (B) 3:2 (C) 2:1 D) 4:3

A straight line through the point A(1,1) meets the parallel lines 4x+2y=9&2x+y+6=0 at points P and Q respectively.Then the point A divides the segment PQ in the ratio:

A straight line through origin O meets the lines 3y=10-4x and 8x+6y+5=0 at point A and B respectively. Then , O divides the degment AB in the ratio.

Two straight lines passing through the point A(3, 2) cut the line 2y=x+3 and x-axis perpendicularly at P and Q respectively. The equation of the line PQ is

A straight-line L through the origin meets the lines x+y=1 and x+y=3 at P and Q respectively. Through P and Q two straight lines L_(1) and L_(2) are drawn, parallel to 2x-y=5 and 3x+y=5 , respectively. Lines L_(1) and L_(2) intersect at R, show that the locus of R as L varies, is a straight line

A line through the point P(2,-3) meets the lines x-2y+7=0 and x+3y-3=0 at the points A and B respectively.If P divides AB externally in the ratio 3:2 then find the equation of the line AB.