Home
Class 14
MATHS
" The equation of motion of projectile i...

" The equation of motion of projectile is "y=ax-bx^(2)" where "a" and "b" are constants."

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of motion of a projectile is y=ax-bx^(2) , where a and b are constants of motion. Match the quantities of column I with the relations of column II.

The equation of motion of a projectile is y = ax - bx^(2) , where a and b are constants of motion. Match the quantities in Column I with the relations in Column II.

The equation of motion of a projectile is y = ax - bx^(2) , where a and b are constants of motion. Match the quantities in Column I with the relations in Column II.

The equation of motion of a projectile is y =ax - bx^2 where a and b are constants of motion. The horizontal range of the projectile is

[" The equation of trajectory of a projectile is "],[y=ax-bx^(2)" where "x" and "y" axes are along "],[" horizontal and vertical directions "],[" respectively.The range of the projectile is "]

A particle moves in the xy plane with a constant acceleration 'g' in the negative-direction. Its equation of motion is y = ax-bx^(2) , where a and b are constants. Which of the following are correct?

If y=a+ bx^(2) , where a, b are constants, then