[" 2.Fing of "theta=5rArr sec theta=],[qquad [2," ) "2," (i) "1," 4) "-1]]

tan^(2)theta+sec theta=5rArr sec theta=

Find (sec^(4)theta-1)/(Sec^(2)theta+1)=

tan2 theta(sec8 theta-1)=tan8 theta(sec4 theta-1)

If 4 sin theta = 3 cos theta , " then " (sec^(2) theta )/( 4 ( 1 - tan^(2) theta )) is

a sec theta + b tan theta = 1, sec theta - b tan theta = 5 rArr a^(2)(b^(2) + 4) =

If 6 sec^(2)theta - 5 sec theta + 1 = 0 then theta =

Prove each of the following identities : (i) (sec^(2) theta -1) cot^(2) theta =1 " " (ii) (sec^(2) theta -1) ("cosec"^(2)theta -1) =1 (iii) (1- cos^(2) theta )sec^(2) theta = tan^(2) theta

Prove that (i) ("cosec"^(2) theta-1 ) tan^(2) theta =1 " " (ii) (sec^(2) theta -1)(1- "cosec"^(2) theta )=-1