[(i),2x+3y+3z=5],[x-2y+z,=-4],[3x-y-2z,=3]

Using matrices, solve the following system of equations for x,y and z: 2x+3y + 3z=5, x-2y + z = -4, 3x-y - 2z=3

Using matrices, solve the following system of equations for x,y and z. 2x+3y+3z=5 , x-2y+z=-4 , 3x-y-2z=3

2x+3y+z=17,x-y+z=3,3x+2y-2z=4

2x-y+z=6,x+2y+3z=3,3x+y-z=4

x+2y-3z=0,3x+3y-z=5,x-2y+2z=1

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.

The system 2x + 3y + z= 5, 3x + y + 5z =7, x + 4y -2z=3 has

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

x+2y-2z=5,3x-y+z=8,x+y-z=4