The area enclosed within the curve `|x|+|y|=1` is

The area enclosed within the curve |x|+2|y|=1 is

The area enclosed between the curves |x| + |y| ge 2 and y ^(2) =4 (1- (x ^(2))/(9)) is :

The area enclosed by the curve max{|x-1|,|y|}=k is 100 ,then k is equal to

Find the area enclosed by the curves max(|x|,|y|)=1

Find the area enclosed by the curves max(2|x|,2|y|)=1

Find the area enclosed by the curves max(|x+y|,|x-y|)=1

Area enclosed by the curve |x-2|+|y+1|=1 is equal to

The area enclosed between the curve y = 1 + x^(2) , the Y-axis and the straight line y = 5 is given by

If A_(1) is the area enclosed by the curve xy=1, x-axis and the ordinates x=1,x=2,and A_(2) is the area enclosed by the curve xy=1, x-axis and the ordinates x=2, x=4, then