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" (1) Erpress "cos^(6)A+sin^(6)A" in ter...

" (1) Erpress "cos^(6)A+sin^(6)A" in terms of "sin2A" ."

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Express cos^(6)A+sin^(6)A in terms of sin2A

Express cos^(6)A + sin^(6)A interms of sin 2A .

sin^(6)A+cos^(6)A is equal to

cos^6A+sin^6A is equal to:

sin^(6)A+cos^(6)A is equal to :

If sin alpha+ cos alpha=n , then sin^(6)alpha+ cos^(6)alpha in terms of n is ________

If sin alpha + cos alpha = lambda then find |sin^(6) alpha - cos^(6) alpha| in terms of lambda .

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)