Statement 1: Each point on the line `y-x+12=0` is equidistant from the lines `4y+3x-12=0,3y+4x-24=0` Statement 2: The locus of a point which is equidistant from two given lines is the angular bisector of the two lines.

The locus of a point equidistant from two intersecting lines is

Statement-1: Each point on the line y-x+12=0 is at same distance from the lines 3x+4y-12=0 and 4x+3y-12=0 statement-2: locus of point which is at equal distance from the two given intersecting lines is the angle bisectors of the two lines.

The point on the line 4x-y-2=0 which is equidistant from the points (-5,6) and (3,2) is

Points on the line x + y = 4 which are equidistant from the lines |x| = |y| , are

The point on the line 2x-3y=5 which is equidistant from (1,2) and (3,4) is

Prove that the locus of a moving point, which is equidistant from the lines 3x-2y=5 and 3x+2y=5 , is a straight line.

Show that the origin is equidistant from the lines 4x+3y+10=0;5x-12y+26=0 and 7x+24y=50