Two natural numbers x and y are chosen at random. What is the probability that `x^(2) + y^(2)` is divisible by 5?

Two natural numbers a and b are selected at random. The probability that a^(2)+b^(2) is divisible by 7 is

Two non-negative integers x and y are chosen at random with replacement. The probability that x^(2)+y^(2) is divisible by 10, is

Two natural numbers x and y are chosen at random from the set {1,2,3,4,...3n}. find the probability that x^(2)-y^(2) is divisible by 3.

Two numbers a and b are chosen at random from the set {1,2,3,..,5n}. The probability that a^(4)-b^(4) is divisible by 5, is

Two numbers a and b are chosen at random from the set {1,2,3,..,3n}. The probability that a^(3)+b^(3) is divisible by 3, is

If x,y,z in N. Then the probability that x^(2)+y^(2)+z^(z) is divisible by 7 is

Two numbers a and b are selected from the set of natural number then the probability that a^(2)+b^(2) is divisible by 5 is

A three digits number was chosen at random. Find the probability that it is divisible by both 2 and 3.

If a number x is chosen at random from the numbers -2,-1,0,1,2. What is the probability that x^(2)<2?

A bag contains 16 cards bearing number 1 , 2 , 3 … , 16 respectively . One card is chosen at random . What is the probability that the chosen card bears a number which is divisible by 3 ?