Statement 1 : The line `x-2y=2` meets the parabola, `y^2 + 2x = 0` only at the points `(-2,2)` Statement 2: The line `y=mx-1/(2m) (m != 0)` is tangent to the parabola, `y^2 =-2x` at the point `(-1/(2m^2),-1/m)`.

Statement 1: The line x-2y =2 meets the parabola y^(2) +2x=0 only at the point (-2,-2) Statement 2: The line y= mx -1//2m (m ne 0 ) is a tangent to the parabola , y ^(2) =-2x at the point (-( 1)/( 2m ^(2)), ( 1)/(m))

The line y=mx+1 is tangent to the parabola y^2=4x if m is _____.

If the line y=mx+1 is tangent to the parabola y^(2)=4x, then find the value of m .

The line y=m x+2 is a tangent to the parabola y^(2)=4 x, then m=

The straight line y=mx+1 is a tangent to the parabola y^2=4x , the find the value of m.

If the line y = mx + 1 is tangent to the parabola y^(2) = 4x then find the value of m.

Line y = mx + 3 is tangent to parabola 3y^(2) = 2x then m = ……..

If the line y=m x+1 is tangent to the parabola y^2=4x , then find the value of m .