In the figure, O is the centre of the circle. Seg AC is the diameter `/_ ABC` is inscribed in arc ABC and intercepts arc AMC then prove `/_ ABC = 90^(@)`

In Figure,AB=CB and O is the centre of the circle.Prove that BO bisects /_ABC .

In the figure, O is the centre of the circle such that /_AOC-140^(@) , then /_ABC="……."

In the figures, /_ABC is inscribed in arc ABC and intercepts arc AXC and /_BCD is inscribed in arc BCD and intercepts arc BYD. If /_ABC = 30^(@) and m ( arc BYD ) = 80^(@) then the m ( arc AXC ) = "…...." and measure of /_ BCD = "…........."

In the given figure , O is the centre of the circle. If m(arc AXB)= 80^@ , then mangleAOB =

In Figure,O is the centre of the circle and the measure of arc ABC is 100^(@). Determine /_ADC and /_ABC

In the given figure,O is the centre of the circle and BA =AC. If /_ABC=50^(@), find /_BOC and /_BDC.

Corollaries of inscribed angle theorem : Angle inscribed in the same arc arc contruent Given : (1) A circle with centre O (2) /_ABD and /_ACD are inscribed in arc ABC and intercepts arc APD. To prove : /_ABD ~= /_ACD

In the following figure, O is the centre of the circle. /_ ABC is inscribed in arc ABC and /_ ABC = 65^(@) . Complete the following activity to find the measure of /_ AOC Activity : /_ ABC = (1)/(2) m square …..(Inscribed angle theorem) :. square xx 2 m (arc AXC) :. m (arc AXC = square /_ AOC = m (arc AXC)... (Definition of measure of minor arc) :. /_ AOC = square

In the picture, O is the centre of the circle and A, B, C are points on it. Prove that /_OAC + /_ABC=90^@

Inscribed Angle Theorem The measure of an inscribed angle is half of the measure of the arc intercepted by it. Given : In a circle with centre O, /_BAC is inscribed in an arc BAC. /_BAC intercepts are BXC of the circle. To prove : m /_BAC = (1)/(2) m ( arc BXC ) .