sqrt(6+sqrt(6+sqrt(6......)))

If tan theta=sqrt(6+sqrt(6+sqrt6+...)) then sec^2 theta=

(sqrt(6)+sqrt(5)+ 1/(sqrt(6)+sqrt(5)))^2

(6 + sqrt6)(6 - sqrt6)

(sqrt(-2))(sqrt(-3)) is equal to sqrt(6)b.-sqrt(6)c.i sqrt(6)d* none of these

Find the angle between the plane x+y-2z+5=0 and the line whose direction cosines are 1/sqrt(6),2/sqrt(6),1/sqrt(6) .

Find the angle between the plane x+y-2z+5=0 and the line whose direction cosines are 1/sqrt(6),2/sqrt(6),1/sqrt(6) .

Rationalise the denominator of (sqrt(7)-sqrt(6))/(sqrt(7)+sqrt(6))

sqrt(7+2sqrt(6))+sqrt(7-2sqrt(6)) =______.