-6quad (" iii ")y^(3)-8y^(2)+17y-10

The Curve represented by the equation 2x^(2)+xy+6y^(2)-2x+17y-12=0 is

Find the centre and radius of each of the circles whose equations are given below: (i) 3x^(2)+3y^(2)-5x-6y+4=0 (ii) 3x^(2)+3y^(2)+6x-12-1=0 (iii) x^(2)+y^(2)+6x+8y-96=0 (iv) 2x^(2)+2y^(2)-4x+6y-3=0 (v) 2x^(2)+2y^(2)-3x+2y-1=0 (vi) x^(2)+y^(2)+2x-4y-4=0 (vii) x^(2)+y^(2)-4x-8y-41=0

Find the centre and radius of each of the circles whose equations are given below: (i) 3x^(2)+3y^(2)-5x-6y+4=0 (ii) 3x^(2)+3y^(2)+6x-12-1=0 (iii) x^(2)+y^(2)+6x+8y-96=0 (iv) 2x^(2)+2y^(2)-4x+6y-3=0 (v) 2x^(2)+2y^(2)-3x+2y-1=0 (vi) x^(2)+y^(2)+2x-4y-4=0 (vii) x^(2)+y^(2)-4x-8y-41=0

(pi)(8y^(2)+6y+1)#(2y+1)

If y=(sqrt(3)+1)/(2) then find the value of 4y^(3)+2y^(2)-8y+10=

x ^ (2) + y ^ (2) + 1, x ^ (2) + 2y ^ (2) + 3, x ^ (2) + 3y ^ (2) + 4y ^ (2) + 2,2y ^ (2) + 6.3y ^ (2) + 8y ^ (2) + 1.2y ^ (2) + 3.3y ^ (2) +4] |

Divide 8y^(3)-6y^(2)+4y-1 by 4y+2. Also write the quotient and the remainder.