समीकरण `Co(s) + Cu^(2+) (aq) to Co^(2-)(aq) + Cu(s) ` है

The reaction Co(s) + Cu^(2+)(aq) rarr Co^(2+)(aq) + Cu(s) is-

What is meant by electrode potential? Explain in the half cell reactions of Zn(s) + Cu^(2+) ( aq) rarr Zn^(2+) (aq) + Cu(s)

Co(s) +Cu^(2+)(aq) rarrCo^(2+)(aq) +Cu(s) .This reaction is :

Represent the galvanic cell in which the reaction, Zn(s) + Cu^(2+) (aq) rarr Zn^(2+) (aq) + Cu(s) take place.

Zn(s) + Cu^(2+)(aq) rarr Zn^(2+)(aq) + Cu(s) The cell representation for the above redox reaction is

Represent the galvanic cell in which the reaction Zn(s)+Cu^(2+) (aq) to Zn^(2+) (aq)+Cu(s) takes place.

E.M.F. of Ni(s) | Ni^(2+) (aq)||Cu^(2+) (aq)| Cu(s) cell can be increased by

E^(@) for the electrochemical cell Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+) 1 M (aq.)|Cu(s) is 1.10 V at 25^(@)C . The equilibrium constant for the cell reaction, Zn(s) +Cu^(2+) (aq.) hArr Zn^(2+) (aq.)+Cu(s) Will be :

E^(@) for the electrochemical cell Zn(s) | Zn^(2+)1M (aq)|| Cu^(2+) 1M(aq)| Cu (s) is 1.10 V at 25^(@) C. The equilibrium constant for the cell reaction, Zn(s)+Cu^(2+) (aq.) rarr Zn^(2+) (aq.) + Cu(s) will be: