In a `DeltaABC , vec(AB) = 6hat i + 3hat j + 3hat k ; vec(AC) = 3hat i-3 hat j + 6hat k D and D`, are points trisections of side BC Find `vec(AD) and vec(AD)'`

If vec a = 6hat i - hat j+ 2hat k and vec b =hat i- 3hat j - 2 hat k , find vec a - vec b .

Vectors vec A=hat i+hat j-2hat k and vec B=3hat i+3hat j-6hat k are

If vec(AB) = 3hat(i) + 2hat(j) + 6hat(k), vec(OA) = hat(i) - hat(j) - 3hat(k) , find the value of vec(OB) .

If vec a=hat i+3hat j-2hat k and vec b=-hat i+3hat k find |vec a xxvec b|

Vector vec(A)=hat(i)+hat(j)-2hat(k) and vec(B)=3hat(i)+3hat(j)-6hat(k) are :

Vector vec(A)=hat(i)+hat(j)-2hat(k) and vec(B)=3hat(i)+3hat(j)-6hat(k) are :

If vec(a) = hat(i) + hat(j) + 2 hat(k) and vec(b) = 3 hat(i) + 2 hat(j) - hat(k) , find the value of (vec(a) + 3 vec(b)) . ( 2 vec(a) - vec(b)) .

The position vectors of points A, B, C and D are : vec(A) = 3hat(i) + 4hat(j) + 5hat(k), vec(B) = 4hat(i) + 5hat(j) + 6hat(k) vec(C ) = 7hat(i) + 9hat(j) + 3hat(k) and vec(D) = 4hat(i) + 6hat(j) Then the displacement vectors vec(AB) and vec(CD) are :