(sin5 alpha-sin3 alpha)/(cos5 alpha+2cos4 alpha+cos3 alpha)=

The value of (sin5alpha-sin3alpha)/(cos5alpha+2cos4alpha+cos3alpha) is

(sin 5 alpha-sin3alpha)/(cos 5 alpha+2 cos 4 alpha+cos 3alpha)=

prove that (sin alpha+sin3 alpha+sin5 alpha)/(cos alpha+cos3 alpha+cos5 alpha)=tan3 alpha

Prove that (sin alpha+sin2 alpha+sin3alpha+sin4alpha)/(cos alpha+cos 2 alpha+cos 3 alpha+cos4 alpha)=tan((5 alpha)/2)

if A,=[[cos alpha,sin alpha-sin alpha,cos alphasin alpha,cos alphacos2 alpha,sin2 alpha-sin2 alpha,cos2 alpha]]

(sin alpha*sin3 alpha+sin3 alpha*sin7 alpha+sin5 alpha*sin15 alpha)/(sin alpha*cos3 alpha+sin3 alpha cos7 alpha+sin5 alpha*cos15 alpha)=

((cos alpha-cos3 alpha)(sin8 alpha+sin2 alpha))/((sin5 alpha-sin alpha)(cos4 alpha-cos6 alpha))=

(( cos alpha - cos 3 alpha ) ( sin 8 alpha + sin 2 alpha ))/( ( sin 5 alpha - sin alpha ) ( cos 4 alpha - cos 6 alpha ))=

sin alpha-sin2 alpha+sin3 alpha=4cos(3 alpha)/(2)cos alpha sin(alpha)/(2)

( sin 8 alpha * cos alpha - sin 6 alpha * cos 3 alpha )/(cos 2 alpha cos alpha - sin 3 alpha * sin 4alpha ) =