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If the magnitudes of two vectors are 3 a...

If the magnitudes of two vectors are 3 and 4 and magnitude of their scalar product is 6 what is the angle between the vectors ?

Text Solution

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Hint `A=3, B=4" "vecA.vecB=6`
`cos theta=(vecA.vecB)/(AB)`
`cos theta=(vecA.vecB)/(AB)=(6)/(3xx4)=(1)/(2)`
`theta=60^(@)`
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