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A force F=(5+2x) acts on a particle in x...

A force `F=(5+2x)` acts on a particle in x direction where F is in newtown and x is meter. Find the work done by this force during displacement from `x=0` to `x=1m.`

Text Solution

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Hint : `F=(5+2x)`
`dW=vecF.dvecx=(5+2x)dx`
Total work done, `W=int_(x=0)^(x=1)(5+2x)dx`
`F=(5+2x)`
`dW=vecF.vec(dx)=(5+2x)dx`
`W=[5x+2.(x^(2))/(2)]_(0)^(1)=5(1-0)+(1^(2)-0)`
`=6J`
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