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A bullet of mass 10 g moving with a velo...

A bullet of mass 10 g moving with a velocity `300 ms^(-1)` strikes a wooden block and comes out from ot her side with a velocity of `200ms^(-1).` Find the work done by t he resistive force on the bullet.

Text Solution

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Hint : `DeltaK=K_(f)-K_(l)=W`
`W=(1)/(2)mv^(2)-(1)/(2)m u^(2)`
`m=10xx10^(-3)kg`
`u=300 m//s`
`v=200m//s`.
`W=K_(f)-K_(i)=(1)/(2)mv^(2)-(1)/(2)m u^(2)=(1)/(2)xx10xx10^(-3)xx(200^(2)-300^(2))`
`=-5xx10^(-3)xx500xx100=-250J`
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