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An engine pumps 800 kg of water through ...

An engine pumps 800 kg of water through height of 10 m in 80 s. Find the power of the engine if its efficiency is `75%`

Text Solution

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Hint : `W=mgh" "Pxx(75)/(100)=(W)/(Deltat)`
Work done by engine against gravity
`W=mgh=800xx10xx10="80 kJ"`
`"Power used by engine "=(W)/(Deltat)=(80xx10^(3))/(80)W=1kW`
If power of the engine is P
Then `Pxx(75)/(100)=1kW`
`Pxx(100)/(75)kW=1.3kW`
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