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A force vecF=(4hati+5hatj)N acts on a pa...

A force `vecF=(4hati+5hatj)N` acts on a particle moving in XY plane. Starting from origin, the particle first goes along x-axis to the point `(5.0)` m and then parallel to the Y-axis to the point `(5,4` m. The total work done by the force on the particle is

A

`+12J`

B

`-6J`

C

`+24J`

D

`-12J`

Text Solution

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The correct Answer is:
C
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