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The PE of a 2 kg particle, free to move ...

The PE of a 2 kg particle, free to move along x-axis is given by `V(x)=((x^(3))/(3)-(x^(2))/(2))J.` The total mechanical energy of the particle is 4 J. Maximum speed (in `ms^(-1)`) is

A

`(1)/(sqrt2)`

B

`sqrt2`

C

`(3)/(sqrt2)`

D

`(5)/(sqrt6)`

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The correct Answer is:
D
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