Home
Class 12
PHYSICS
The velocity (in m/s) of an object chan...

The velocity (in m/s) of an object changes from ` vecv_(1) = 10 hati + 4hatj + 2hatk " to " vecv_(2) = 4hati + 2hatj + 3hatk` in 5 second. Find the magnitude of average acceleration.

Text Solution

Verified by Experts

The correct Answer is:
`1.28 m.s^(-2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Given veca = hati-hatj+hatk and vecb = 2hati-4hatj-3hatk , find the magnitude of veca

Velocity of a particle of mass 2 kg change from vecv_(1) =-2hati-2hatjm/s to vecv_(2)=(hati-hatj)m//s after colliding with as plane surface.

The velociies of A and B are vecv_(A)= 2hati + 4hatj and vecv_(B) = 3hati - 7hatj , velocity of B as observed by A is

Velocity of a particle changes from (3hati +4hatj)m//s to (6hati +5hatj)m//s 2s. Find magnitude and direction of average acceleration.

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s) . Find the acceleration at t = 2s.