How many moles of lead nitrate is needed to produce 224 litre of oxygen at NTP?

Explanation

To determine how many moles of lead nitrate (Pb(NO₃)₂) are needed to produce 224 liters of oxygen (O₂) at Normal Temperature and Pressure (NTP), we can follow these steps:

### Step 1: Write the balanced chemical equation
The decomposition of lead nitrate can be represented by the following balanced equation:

\[ 2 \text{Pb(NO}_3\text{)}_2 \rightarrow 2 \text{PbO} + 4 \text{NO}_2 + \text{O}_2 \]

From this equation, we can see that 2 moles of lead nitrate produce 1 mole of oxygen.
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