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A solution is prepared by adding 360 g o...

A solution is prepared by adding 360 g of glucose to 864 g of water. Calculate mole fraction of glucose (molar mass of glucose = 180).

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`"No. of moles of glucose"= (360)/(180)= 2`
`"No. of moles of water"= (864)/(18)= 48`
`therefore "Mole fraction of glucose"= (2)/(2+48)= (2)/(50)= (1)/(25)= 0.04`
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