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when 8.4 g of NaHCO(3) is added to a:sol...

when 8.4 g of `NaHCO_(3)` is added to a:solution of `CH_(3)COOH` Weighing 20g. it is observed that 4.4 g of `CO_(2)` is released into atmosphere and a residue is left behind. Calculate the mass of residue by applying law of conservation of mass.

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To solve the problem, we will apply the law of conservation of mass, which states that the mass of the reactants is equal to the mass of the products. ### Step-by-Step Solution: 1. **Identify the Mass of Reactants**: - Mass of `NaHCO3` = 8.4 g - Mass of `CH3COOH` = 20 g - Total mass of reactants = Mass of `NaHCO3` + Mass of `CH3COOH` ...
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When 6.4 g of NaHCO_(3) is added to a solution of CH_(3)COOH weighing 20. It is observed that 4.4 g of CO_(2) is released into atmosphere and a residue is left behind Calculate the mass of residue by applying law of conservation of mass.

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a. When 4.2 g NaHCO_(3) is added to a solution of CH_(3)COOH is released into atomosphere. The residue is the found to weigh 12.0g . Show that these observations are in agreement with the low of conservation of weigh. b. If 6.3 g of NaHCO_(3) are added to 15.0 g CH_(3)COOH solution. The residue is found to weigh 18.0 g what is the mass of CO_(2) released in this reaction?

If 6.3 g of NaHC O_(3) are added to 15.0 g CH_(3) COOH solution, the residue is found of weight 18.0 g. What is the mass of CO_(2) released in the reaction?

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