The number of atoms in 0.1 mol of a tetraatomic gas is (`N_(A) = 6.02 xx 10^(23) mol^(-1)`)

Options

A. `2.4 xx 10^(22)`
B. `6.026 xx 10^(22)`
C. `2.4 xx 10^(23)`
D. `3.600 xx 10^(23)`

Answer

To find the number of atoms in 0.1 moles of a tetraatomic gas, we can follow these steps:

### Step 1: Understand the concept of moles and Avogadro's number
- Avogadro's number (\(N_A\)) is the number of particles (atoms, molecules, etc.) in one mole of a substance. It is given as \(6.02 \times 10^{23} \, \text{mol}^{-1}\).

### Step 2: Determine the number of molecules in 0.1 moles
- The number of molecules in a given number of moles can be calculated using the formula:
\[ \text{Number of molecules} = \text{Number of moles} \times N_A \]
- For 0.1 moles of the gas:
\[ \text{Number of molecules} = 0.1 \, \text{mol} \times 6.02 \times 10^{23} \, \text{mol}^{-1} \]
\[ \text{Number of molecules} = 0.1 \times 6.02 \times 10^{23} = 6.02 \times 10^{22} \, \text{molecules} \]

### Step 3: Calculate the number of atoms in the tetraatomic gas
- Since the gas is tetraatomic, each molecule contains 4 atoms. Therefore, the total number of atoms can be calculated as:
\[ \text{Number of atoms} = \text{Number of molecules} \times \text{Number of atoms per molecule} \]
- Substituting the values:
\[ \text{Number of atoms} = 6.02 \times 10^{22} \, \text{molecules} \times 4 \, \text{atoms/molecule} \]
\[ \text{Number of atoms} = 24.08 \times 10^{22} = 2.408 \times 10^{23} \, \text{atoms} \]

### Final Answer
- The number of atoms in 0.1 moles of a tetraatomic gas is approximately:
\[ 2.4 \times 10^{23} \, \text{atoms} \]