`6.025 xx 10^(20)` molecules of acetic acid are present in 500 ml of its solution. The concentration of solution is

Options

A. 0.002 M
B. 10.2 M
C. 0.012 M
D. 0.001 M

Answer

To find the concentration of acetic acid in the solution, we will follow these steps:

### Step 1: Calculate the number of moles of acetic acid
We know that the number of molecules of acetic acid is given as \(6.025 \times 10^{20}\) molecules. To convert this to moles, we use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) molecules per mole.

\[ \text{Number of moles} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} = \frac{6.025 \times 10^{20}}{6.022 \times 10^{23}} \]

Calculating this gives:

\[ \text{Number of moles} = \frac{6.025}{6.022} \times 10^{20 - 23} = 1.0005 \times 10^{-3} \text{ moles} \]

### Step 2: Convert the volume of the solution from milliliters to liters
The volume of the solution is given as 500 ml. To convert this to liters, we use the conversion factor \(1 \text{ L} = 1000 \text{ ml}\).

\[ \text{Volume in liters} = \frac{500 \text{ ml}}{1000} = 0.5 \text{ L} \]

### Step 3: Calculate the concentration of the solution
Concentration (C) is defined as the number of moles of solute (n) divided by the volume of the solution in liters (V).

\[ C = \frac{n}{V} = \frac{1.0005 \times 10^{-3} \text{ moles}}{0.5 \text{ L}} \]

Calculating this gives:

\[ C = 2.001 \times 10^{-3} \text{ mol/L} = 0.002001 \text{ M} \]

### Final Answer
The concentration of the acetic acid solution is approximately \(0.002 \text{ M}\).

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