Why electron cannot exist inside the nucleus according to Heisenberg's uncertainty principle?

Explanation

Diameter of the atomic nucleus is of the order of `10^(-15)` m
` therefore ` The maximum uncertainty in the electron is `10 ^(-15)` m
Mass of electron `=9.1xx10^(-31) Kg`
Now
` Delta x. Deltap=(h)/(4 pi)`
` Delta x xx ( m Delta v ) =(h)/(4 pi)`
`Delta V =(h)/(4 pi) xx (1)/( Delta x-m) = ( 6.626 xx10^(-34))/(4xx((22)/(7)))xx (1)/(10^(-15)xx9.1xx10^(-31))`
`Delta v=5.80 xx 10^(10) ms^(-1)`
this value is much higher than the velocity of light and hence it is not possible