Calculate the frequency and wavelength of photon with energy `3.98 xx 10^(-15)J`

Explanation

energy of photon :
(a) Frequency of photon :
E= hc (planck.s quantum theory )
`3.98 xx10 ^(-15) J = 6.626 xx10 ^(-34) Js xxv `
`v=(3.98 xx10^(-15) J)/(6.626 xx10 ^(-34)Js)`
Frequency `=6.0xx10 ^(18) s^(-1) (Hz)`
(b ) wavelength of photon :
` lamda =(c )/(v )`
` lamda = ( 3xx10 ^(8) ms^(-1))/(6.0 xx10^(18)s^(-1))`
` =0.5xx10^(-10) m`
Wavelength `= 0.5Å ( 1A = 10^(-10) m)`