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Photoelectrons are removed with kinetic ...

Photoelectrons are removed with kinetic energy `1.864 xx 10^(-21)J`, when photons of light with energy ` 4.23 xx 10^(-19) J` fall on the metal. What is the minimum energy required per mole to remove an electron potassium metal?
Hing`: hv_(0)= hv-KE`
Energy required per mole `=hv_(0) xx 6.022 xx 10^(23)`

Text Solution

Verified by Experts

`hv_0 = hv - KE`
energy required pre mole ` = hv_0 xx 6.022 xx 10 ^(23)` s
`253 . KJ mol ^(-1)`
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