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In hydrogen atom, energy of first excit...

In hydrogen atom, energy of first excited state is `- 3.4 eV`. Then, `KE` of the same orbit of hydrogen atom is.

A

`+3.4 eV`

B

`+6.8 eV`

C

`-13.6 ev`

D

`+13.6`eV

Text Solution

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The correct Answer is:
A
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