Draw the lewis structure of `H_(2)O_(2)` (hydorgen peroxide )

Explanation

To draw the Lewis structure of hydrogen peroxide (H₂O₂), follow these steps:

### Step 1: Determine the total number of valence electrons
- Hydrogen (H) has 1 valence electron, and since there are 2 hydrogen atoms, they contribute a total of \(2 \times 1 = 2\) valence electrons.
- Oxygen (O) has 6 valence electrons, and since there are 2 oxygen atoms, they contribute a total of \(2 \times 6 = 12\) valence electrons.
- Therefore, the total number of valence electrons in H₂O₂ is \(2 + 12 = 14\) valence electrons.

### Step 2: Arrange the atoms
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