Draw the lewis structure of `NO_(2)^(-)` (Nitrite ion).

Explanation

To draw the Lewis structure of the nitrite ion, \( \text{NO}_2^{-} \), we will follow these steps:

### Step 1: Determine the total number of valence electrons.
- Nitrogen (N) has 5 valence electrons.
- Each Oxygen (O) has 6 valence electrons, and since there are two oxygens, that contributes \( 2 \times 6 = 12 \) electrons.
- The nitrite ion has an overall negative charge (-1), which means we add 1 more electron.

Total valence electrons = \( 5 + 12 + 1 = 18 \) electrons.
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