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Which one of the following has the stron...

Which one of the following has the strongest O - O bond?

A

`O_(2)^(+)`

B

`O_(2)`

C

`O_(2)^(-)`

D

`O_(2)^(2-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given species has the strongest O-O bond, we need to calculate the bond order for each species: O2, O2^+, O2^-, and O2^2-. The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} \left( \text{Number of electrons in bonding orbitals} - \text{Number of electrons in antibonding orbitals} \right) \] ### Step 1: Determine the Electron Configuration of O2 Oxygen (O) has 8 electrons, so O2 has a total of 16 electrons. The molecular orbital configuration for O2 is: - σ(1s)² σ*(1s)² - σ(2s)² σ*(2s)² - σ(2p)², π(2p_x)², π(2p_y)², π*(2p_x)¹, π*(2p_y)¹ Counting the electrons: - Bonding: 2 (σ(1s)) + 2 (σ(2s)) + 2 (σ(2p)) + 2 (π(2p_x)) + 2 (π(2p_y)) = 10 - Antibonding: 2 (σ*(1s)) + 2 (σ*(2s)) + 1 (π*(2p_x)) + 1 (π*(2p_y)) = 6 ### Step 2: Calculate Bond Order for O2 Using the bond order formula: \[ \text{Bond Order} = \frac{1}{2} (10 - 6) = \frac{4}{2} = 2 \] ### Step 3: Determine the Electron Configuration of O2^- For O2^-, we add one additional electron: - New configuration: σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² σ(2p)², π(2p_x)², π(2p_y)², π*(2p_x)² Counting the electrons: - Bonding: 10 (same as O2) - Antibonding: 6 + 1 = 7 Calculating bond order: \[ \text{Bond Order} = \frac{1}{2} (10 - 7) = \frac{3}{2} = 1.5 \] ### Step 4: Determine the Electron Configuration of O2^2- For O2^2-, we add two additional electrons: - New configuration: σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² σ(2p)², π(2p_x)², π(2p_y)², π*(2p_x)², π*(2p_y)² Counting the electrons: - Bonding: 10 (same as O2) - Antibonding: 6 + 2 = 8 Calculating bond order: \[ \text{Bond Order} = \frac{1}{2} (10 - 8) = \frac{2}{2} = 1 \] ### Step 5: Determine the Electron Configuration of O2^+ For O2^+, we remove one electron: - New configuration: σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² σ(2p)², π(2p_x)², π(2p_y)², π*(2p_x)² Counting the electrons: - Bonding: 10 (same as O2) - Antibonding: 6 - 1 = 5 Calculating bond order: \[ \text{Bond Order} = \frac{1}{2} (10 - 5) = \frac{5}{2} = 2.5 \] ### Step 6: Compare Bond Orders Now we compare the bond orders: - O2: 2 - O2^-: 1.5 - O2^2-: 1 - O2^+: 2.5 ### Conclusion The species with the strongest O-O bond is O2^+ with a bond order of 2.5.
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