Which compound has tetrachedral structure ?

Options

A. `XeF_(4)`
B. `XeOF_(2)`
C. `XeO_(2)F_(2)`
D. `XeO_(4)`

Answer

To determine which compound has a tetrahedral structure, we need to analyze the hybridization and the number of bond pairs and lone pairs in each given compound. The tetrahedral structure corresponds to sp³ hybridization, which has 4 bond pairs and 0 lone pairs.

### Step-by-Step Solution:

1. **Understanding Tetrahedral Structure**:
- A tetrahedral structure is characterized by sp³ hybridization.
- In sp³ hybridization, there are 4 bond pairs and 0 lone pairs.

2. **Analyzing the Given Compounds**:
- We will evaluate each compound one by one to find their hybridization and structure.

3. **Compound 1: Xenon Tetrafluoride (XeF₄)**:
- Valence electrons of Xenon (Xe) = 8
- Number of monovalent atoms (F) = 4
- Total = 8 + 4 = 12
- Hybridization = (12/2) = 6 → sp³d²
- Structure: Octahedral (not tetrahedral).

4. **Compound 2: Xenon Oxyfluoride (XeOF₂)**:
- Valence electrons of Xenon (Xe) = 8
- Number of monovalent atoms (O and F) = 2
- Total = 8 + 2 = 10
- Hybridization = (10/2) = 5 → sp³d
- Structure: Trigonal bipyramidal (not tetrahedral).

5. **Compound 3: Xenon Oxyfluoride (XeO₂F₂)**:
- Valence electrons of Xenon (Xe) = 8
- Number of monovalent atoms (O and F) = 2
- Total = 8 + 2 = 10
- Hybridization = (10/2) = 5 → sp³d
- Structure: Seesaw (not tetrahedral).

6. **Compound 4: Xenon Tetraoxide (XeO₄)**:
- Valence electrons of Xenon (Xe) = 8
- Number of monovalent atoms = 0 (since O is divalent)
- Total = 8 + 0 = 8
- Hybridization = (8/2) = 4 → sp³
- Structure: Tetrahedral (4 bond pairs, 0 lone pairs).

7. **Conclusion**:
- The compound with a tetrahedral structure is **Xenon Tetraoxide (XeO₄)**.

### Final Answer:
The compound that has a tetrahedral structure is **Xenon Tetraoxide (XeO₄)**.