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In the following questions, a statement ...

In the following questions, a statement of assertion (A) is followed by a statement of reason (R )
A : Bond order of `H_(2)^(+)` is 0.5
R : Electrons are removed from the antibonding molecular orbital from `H_(2)` .

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false, then mark (3)

D

If both Assertion and Reason are false statements , then mark (4).

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both the assertion (A) and the reason (R) given in the question. ### Step-by-Step Solution: 1. **Understanding the Assertion (A)**: - The assertion states that the bond order of \( H_2^+ \) is 0.5. - To determine the bond order, we use the formula: \[ \text{Bond Order} = \frac{(\text{Number of electrons in bonding orbitals}) - (\text{Number of electrons in antibonding orbitals})}{2} \] 2. **Molecular Orbital Configuration of \( H_2 \)**: - For \( H_2 \), the molecular orbital configuration is: - Bonding orbital: \( \sigma_{1s} \) (2 electrons) - Antibonding orbital: \( \sigma^*_{1s} \) (0 electrons) - Thus, the bond order for \( H_2 \) is: \[ \text{Bond Order} = \frac{2 - 0}{2} = 1 \] 3. **Molecular Orbital Configuration of \( H_2^+ \)**: - \( H_2^+ \) has one less electron than \( H_2 \). Therefore, it has 1 electron in the bonding orbital \( \sigma_{1s} \) and 0 electrons in the antibonding orbital \( \sigma^*_{1s} \). - The bond order for \( H_2^+ \) is calculated as follows: \[ \text{Bond Order} = \frac{1 - 0}{2} = 0.5 \] 4. **Understanding the Reason (R)**: - The reason states that electrons are removed from the antibonding molecular orbital of \( H_2 \). - However, when forming \( H_2^+ \), the electron is actually removed from the bonding orbital \( \sigma_{1s} \), not from the antibonding orbital \( \sigma^*_{1s} \). 5. **Conclusion**: - The assertion (A) is true because the bond order of \( H_2^+ \) is indeed 0.5. - The reason (R) is false because electrons are not removed from the antibonding orbital. - Therefore, the correct option is that the assertion is true but the reason is false. ### Final Answer: The correct option is **3. Assertion is true but reason is false.**
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