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If water vapour is assumed to be a perfe...

If water vapour is assumed to be a perfect gas, molar enthalpy change for vaporization of 1 mol of water at 1 bar and `100^(@)C` is `51 kJ mol ^(-1)`. Calculate the internal energy, when 1 mol of water is vapourised at one bar pressure and `100^(@)C`.

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To calculate the internal energy change (ΔU) when 1 mole of water is vaporized at 1 bar pressure and 100°C, we can use the relationship between enthalpy change (ΔH) and internal energy change (ΔU) for an ideal gas. The relationship is given by the equation: \[ \Delta H = \Delta U + P \Delta V \] ### Step 1: Identify the given values - Molar enthalpy change for vaporization (ΔH) = 51 kJ/mol ...
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