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S(("rhombic"))+O(2(g))rarr SO(2(g)) , De...

`S_(("rhombic"))+O_(2(g))rarr SO_(2(g)) , Delta H =-297.5 K J`
`S_(("monoclinic"))+O_(2(g))rarr SO_(2) , Delta H = - 300 K J`
The data can predict that -

A

Rhombic sulphur is yellow in colour

B

Monoclinic sulphur has metallic lustre

C

Monoclinic sulphur is more stable

D

`Delta H_(Transition) of S(R) to S(M)` is endothermic process

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The correct Answer is:
D
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S( rhombic ) + O_(2) rarr SO_(2)," " DeltaH=-297.5kJ S( monoclini ) + O_(2) rarr SO_(2), " "DeltaH=-300kJ This date indicates :

Consider the reactions (i) S (rhombic) + 3//2O_(2) (g) rarr SO_(3) (g), Delta H_(1) (ii) S (monoclinic) +3//2O_(2) (g) rarr SO_(3) (g), Delta H_(2) (iii) S(rhombic) +O_(3) (g) rarr SO_(3) (g) , Delta H_(3) (iv) S (monoclinic) +O_(3)(g) rarr SO_(3) (g), Delta H_(4) incorrect statement is

Using the following thermochemical equations : S("rhombic") + 3/2 O_(2)(g) rarr SO_(3)(g), " "Delta H = - 2x kJ mol^(-1) II. SO_(2)(g) + 1/2 O_(2)(g) rarr SO_(3)(g), " "Delta H = -Y kJ mol^(-1) Find out the heat of formation of SO_(2)(g) in kJ mol^(-1) .

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