The following concentration were obtained for the formation of `NH_3` from `N_2 and H_2` at equilibrium for the reaction `N_2(g) +3H_2(g) hArr 2NH_3(g)`
`[N_2]=1.5 xx 10^(-2) M`
`[H_2]=3.0 xx 10^(-2) M`
`[NH_3]=1.2 xx 10^(-2) M `
Calculate equilibrium constant.

Explanation

To calculate the equilibrium constant \( K_c \) for the reaction

\[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \]

we will use the equilibrium concentrations provided:

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