The value of the equilibrium constant for the reaction
`H_2(g) +I_2(g) hArr 2HI(g)`
at 720 K is 48 . What is the value of the equilibrium constant for the reaction.
`1/2 H_2(g) +1/2 I_2(g) hArr HI(g)`

Explanation

To find the equilibrium constant for the reaction:

\[ \frac{1}{2} H_2(g) + \frac{1}{2} I_2(g) \rightleftharpoons HI(g) \]

given that the equilibrium constant \( K \) for the reaction:

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