If ionisation constant of an acid (HA) at equilibrium is `1.0xx10^(-8)` then calculate the value of `pK_a and pK_b` (for its conjugate base).

Explanation

To solve the problem, we need to calculate the values of \( pK_a \) and \( pK_b \) for the given acid \( HA \) with an ionization constant \( K_a = 1.0 \times 10^{-8} \).

### Step 1: Calculate \( pK_a \)

The formula for \( pK_a \) is given by:

\[
pK_a = -\log(K_a)
...